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The force P is applied to the 67-kg block when it is at rest. Determine the magnitude and direction of the friction force exe

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Nt Psinig Peos 19 N+ Psinmga Fret Pos 19 mg sin It PEo, N=mg s Psinis N fricten favce 0.17 x 67x9.8 xCes1 paand) (dur to ngsiP- 185N Net up ward frePeas 19mg sinit 49.64N - 4 1-12S 28 my Cos Psin 13-(i09.6-Go22) = 19.36 frietion force stetie) >0.17 Ya initiate motian wenees force P Cos P stn 19 o 14 (m cos 17 (5.88t Sin 13) P109.6 109 6 - P> 6 21 17 65 N

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