Question

The force P is applied to the 49-kg block when it is at rest. Determine the magnitude and direction of the friction force exerted by the surface on the block if (a) P = 0, (b) P = 219 N, and (c) P = 311 N. (d) What value of P is required to initiate motion up the incline? The static and kinetic coefficients of friction between the block and the incline are μs = 0.29 and μk = 0.25, respectively. The friction force is positive if up the incline, negative if down the incline.

49 kg V/ 20 4, = 0.29 M = 0.25 17° Answers: Z Z Z Z

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Ques 49kg 120 ins (static hk (Kinetic friction coefficient) = 0.29 friction coefficient) = 0.25 @ when P=0 hores 499 SDI matiF = Fmaxo SO IF = 114.92N © when P = 219 N Fs) maxo = vhs x (4.99 Cositº - psin 20) Fstmaxo = 111:58 N Force along inclined fOPATE / 1201 F - Fe) more che (499c8s 17º – Ps in 20°) = 88.3294 N so F = 88·3294 N to initiate @ what value of p is required

When the body comes in motion kinetic friction comes in picture but in case of rest static friction comes in picture.

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