Question

mass particle mass 239 94 Pu 239.0522 u on 1.0086649 u 0 10 -4 5.4858 x 10 u He 4.00260 297 Cm 242.0588 u 0 -4 5.4858 x 10 u Now consider the following nuclear reaction: He 29Cm + on 239 + -. O released absorbed x ? is energy released or absorbed by this reaction? neither released nor absorbed O I need more information to decide If you said energy was released or absorbed, calculate how much energy is released or absorbed. Give your answer in both kJ/mol and Mev. Round each of your answers to 3 significant digits. w/mol Mev Note: take particular care to keep enough digits in any Intermediate calculation, and use enough digits in any scientific constants you need, since the data with which you are working are very precise.

Answer 1

0 Since it is an example of fusion sean : energy will be released 239 ut 4 in He "Cmt 96 94 242.0583 u 239.05220 4.00260u 1.0086649 u 243.0548 249.06746 Ami mass deject) = Mass g poduct -mass og Reactant 843.0674-2 43.0548 0.01260 0.0126 X1-66X/0 2.09 X lo 29 Rey 19 kg Energy released Amcd (3.01810-999) (9x103) Gysely 2,0989 x 10-13 I 1.8 x10-12 J 1,8x 10 h for I mole E= 118810 9x 6.02 X1083 10.83 X1014 kJ/mol Energy in Mev 1 KJ = 6. 2481015 Mev E = 0.288x10Mer

0 Since it is an example of fusion sean : energy will be released 239 ut 4 in He "Cmt 96 94 242.0583 u 239.05220 4.00260u 1.0086649 u 243.0548 249.06746 Ami mass deject) = Mass g poduct -mass og Reactant 843.0674-2 43.0548 0.01260 0.0126 X1-66X/0 2.09 X lo 29 Rey 19 kg Energy released Amcd (3.01810-999) (9x103) Gysely 2,0989 x 10-13 I 1.8 x10-12 J 1,8x 10 h for I mole E= 118810 9x 6.02 X1083 10.83 X1014 kJ/mol Energy in Mev 1 KJ = 6. 2481015 Mev E = 0.288x10Mer