Question

Imported from se 16. Identity the hybridization of each carbon atom in the following molecule. (The arrangement of atoms is given you need to determine how many bonds connect each por of atoms) HH Hн HC1 C2 C3 C4 C5 C6 H HH A C1 B. C2 C. C3 D. CA E. Cs F. CB 17. For which of the following compounds do cis- and trans-isomers exist? (2) A. 3 only B. 1 and 2 C. 2 and 3 D. 2 only E. 1 only 18. What volume of a pure liquid (density 0.910 g/mL) has a mass of 0.490 kg? A. 4.56 x 10mL B. 1.86 x 100 mL C.5.38 x 102mL D. 446 mL E. 0.0538 L

Answer 1

Solution:

16) Hybridization of Carbon can be simply calculated by knowing the numbers of atoms directly attached to the Carbon. The Carbon may have 2, 3 and 4 atoms directly attached, so the Carbon will have sp, sp2, sp3 hydridization, respectively.

A) C1 has 4 atoms attached ( 3H and C2 ). So, C1 will have Sp3 hydridization. So, C1 has Sp3 hydridization.

B) C2 has 4 atoms attached ( 2H, C1, C3 ). So, C2 will have Sp3 hydridization. So, C2 has Sp3 hydridization.

C) C3 has 2 atoms attached ( C2, C4 ). So, C3 will have Sp hybridization. So, C3 has Sp hybridization.

D) C4 has 2 atoms attached ( C3, C5 ). So, C4 will have Sp hybridization. So, C4 has Sp hybridization.

E) C5 has 3 atoms attached ( H, C4, C6 ). So, C5 will have Sp2 hybridization. So, C5 has Sp2 hybridization.

F) C6 has 3 atoms attached ( 2H, C5 ). So, C6 will have Sp2 hybridization. So, C6 has Sp2 hybridization.

17) For a Compound to exhibit Cis - trans isomerism, it must have an alkene. We can say that the main condition for Cis - trans isomerism to occur is that the compound should have a double bond character, hence it should be an alkene.

As compound (1) and (2) exhibits double bond but compound (3) does not. So, (1) and (2) will show Cis trans isomerism while (3) will not.

Hence, Option B ( 1 and 2 ) is the correct answer.

18) Given, Density (D) = 0.910 g/mL

Mass (m) = 0.490 Kg or 490 gm

We need to calculate Volume(V).

We know, Density (D) = Mass (M) / Volume (V)

Or, Volume (V) = Mass (M) / Density (D)

So, Volume (V) = ( 490 gm ) / ( 0.910 g/mL )

Or, Volume (V) = 446 mL

So, the Volume (V) of pure liquid = 446 mL

Hence, Option D, ( 446 mL ) is the correct answer.