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Radical Reactions Problem-Solving Activity 1. Explain why the radical bromination of the compound below forms A...
What is Wrong? Select the keyword or phrase that will best complete each sentence. Key terms: A radical...
What is Wrong?
Select the keyword or phrase that will best complete each sentence. Key terms: A radical is a reactive intermediate with a single unpaired electron, formed by homoloysis of a covalent bond. paired unpaired Allylic radicals are stabilized by resonance, making them more stable than tertiary radicals increases inductive effects A compound that contains an especially weak bond that serves as a source of radicals is called a radical initiator ess homoloysis decreases more J Treatment of cyclohexene...
Answer the following questions about radical halogenation QUESTION 1 Performing allylic bromination of an asymmetric alkene...
Answer the following questions about radical halogenation
QUESTION 1 Performing allylic bromination of an asymmetric alkene produces two regiochemical outcomes due to resonance, and two conformations (R) and (S) for each chirality center produced. This is further complicated if you make the mistake of using Br2 as your source of bromine radicals, as the addition reaction producing alkyl dibromides competes with the allylic bromination. Br2, hv ??? Categorize each of the compounds shown below as an [A] allylic bromination product,...
Pls ans both a and b. pls remember to explain why pls answer this one also
pls
ans both a and b. pls remember to explain why
pls answer this one also
s Phopose s lausihic ep Write a mechanism for the reaction shown below. You must show the activated complex for both brominated positions. Based on the stability of the activated complex, propose the expected product (c-2 or C-3 bromination). Br2 Br a) FeBr3 Br Only one product is formed. Which one? Why? CH2Cl2 b) AlCl 1, NaOCH3 2. H3O NO2 NO2 OCH3 Cl
s...
Mechanisms Question 1 (22 marks) (a) Consider the radical chain reactions of the alkane shown below with Br, in the...
Mechanisms Question 1 (22 marks) (a) Consider the radical chain reactions of the alkane shown below with Br, in the presence of light. H3C HH H C-CCHS CH3 Br2 hv 2 Different mono- bromo products 25 °C + (you will need to look up the bond dissociation energy (BDE) for the types of bonds formed and broken in this reactions) (i) Give the structures of the products from the reaction and using standard arrow conventions show the series of mechanistic...
Based on the following reactions, explain why Step B is faster than Step A. Br NaOH...
Based on the following reactions, explain why Step B is faster than Step A. Br NaOH ů NaOH Br2 Br Br Br2 A B
Based on the following reactions, explain why Step B is faster than Step A. مل NaOH...
Based on the following reactions, explain why Step B is faster than Step A. مل NaOH Br2 ور Br NaOH Br -Br Br2 A B
pleas help 5,6,7,8,9,10 III IV 5. The product of free-radical halogenation reactions is an alkyl halide....
pleas help 5,6,7,8,9,10
III IV 5. The product of free-radical halogenation reactions is an alkyl halide. The major amount of this halide forms during the second step of propagation. However, you should be aware that one possible termination step also forms alkyl halides. Why does the majority of the alkyl halide product come from the propagation step and not the termination step? A. At any given time during the reaction, the concentration of both the alkyl radical and the halide...
(a) Bromination of 2-methylpropane gives a mixture of brominated products. Compound B, with the formula C4H8Br2,...
(a) Bromination of 2-methylpropane gives a mixture of brominated products. Compound B, with the formula C4H8Br2, was isolated from the mixture. (i) Draw and name the possible isomers of C4H2Br2 that could be formed from 2-methylpropane. [3 marks] (ii) The 'H NMR spectrum of compound B is shown below. Integral = 3 Integral = 1 6 4 0 (ppm) Identify which of the isomers you drew in part i) corresponds to this spectrum. You should clearly explain your reasoning, using...
My teacher is that A is not the major product. please explain why and what would...
My teacher is that A is not the major product. please explain
why and what would be the major
22) (9 points) For the following reaction: a. (5 points) Draw a complete and detailed mechanism for the process shown below to form compounds A and B. mention whether it is initiation, propagation or termination. b/ (2 points) Explain why this reaction gives a mixture of compounds A and B and does not give compound C c. (2 points) Which product...
1.1What is the major product formed upon radical bromination of (S)-3-methylhexane? Select the best response. Draw...
1.1What is the major product formed upon radical bromination of (S)-3-methylhexane? Select the best response. Draw the full mechanism. A. (S)-3-bromo-3-methylhexane B. (R)-3-bromo-3-methylhexane C. A mixture of (R) and (S) 3-Bromo-3-methylhexane D. (3R)-1-bromo-3-methylhexane 1.2 What is the major product obtained from the reaction of 2-methyl-2-butene with hydrogen bromide in the presence of peroxides?Select the best response. Draw the mechanism. A. 2,3-dibromo-2-methylbutane B. 2-bromo-3-methylbutane C. 2-bromo-2-methylbutane D. (E)-1-bromo-2-methyl-2-butene 1.3 There are 4 major products formed upon treatment of (E)-3-methyl-2-hexene with HBr...
What is Wrong?
Select the keyword or phrase that will best complete each sentence. Key terms: A radical is a reactive intermediate with a single unpaired electron, formed by homoloysis of a covalent bond. paired unpaired Allylic radicals are stabilized by resonance, making them more stable than tertiary radicals increases inductive effects A compound that contains an especially weak bond that serves as a source of radicals is called a radical initiator ess homoloysis decreases more J Treatment of cyclohexene...
Answer the following questions about radical halogenation
QUESTION 1 Performing allylic bromination of an asymmetric alkene produces two regiochemical outcomes due to resonance, and two conformations (R) and (S) for each chirality center produced. This is further complicated if you make the mistake of using Br2 as your source of bromine radicals, as the addition reaction producing alkyl dibromides competes with the allylic bromination. Br2, hv ??? Categorize each of the compounds shown below as an [A] allylic bromination product,...
pls
ans both a and b. pls remember to explain why
pls answer this one also
s Phopose s lausihic ep Write a mechanism for the reaction shown below. You must show the activated complex for both brominated positions. Based on the stability of the activated complex, propose the expected product (c-2 or C-3 bromination). Br2 Br a) FeBr3 Br Only one product is formed. Which one? Why? CH2Cl2 b) AlCl 1, NaOCH3 2. H3O NO2 NO2 OCH3 Cl
s...
Mechanisms Question 1 (22 marks) (a) Consider the radical chain reactions of the alkane shown below with Br, in the presence of light. H3C HH H C-CCHS CH3 Br2 hv 2 Different mono- bromo products 25 °C + (you will need to look up the bond dissociation energy (BDE) for the types of bonds formed and broken in this reactions) (i) Give the structures of the products from the reaction and using standard arrow conventions show the series of mechanistic...
Based on the following reactions, explain why Step B is faster than Step A. Br NaOH ů NaOH Br2 Br Br Br2 A B
Based on the following reactions, explain why Step B is faster than Step A. مل NaOH Br2 ور Br NaOH Br -Br Br2 A B
pleas help 5,6,7,8,9,10
III IV 5. The product of free-radical halogenation reactions is an alkyl halide. The major amount of this halide forms during the second step of propagation. However, you should be aware that one possible termination step also forms alkyl halides. Why does the majority of the alkyl halide product come from the propagation step and not the termination step? A. At any given time during the reaction, the concentration of both the alkyl radical and the halide...
(a) Bromination of 2-methylpropane gives a mixture of brominated products. Compound B, with the formula C4H8Br2, was isolated from the mixture. (i) Draw and name the possible isomers of C4H2Br2 that could be formed from 2-methylpropane. [3 marks] (ii) The 'H NMR spectrum of compound B is shown below. Integral = 3 Integral = 1 6 4 0 (ppm) Identify which of the isomers you drew in part i) corresponds to this spectrum. You should clearly explain your reasoning, using...
My teacher is that A is not the major product. please explain
why and what would be the major
22) (9 points) For the following reaction: a. (5 points) Draw a complete and detailed mechanism for the process shown below to form compounds A and B. mention whether it is initiation, propagation or termination. b/ (2 points) Explain why this reaction gives a mixture of compounds A and B and does not give compound C c. (2 points) Which product...
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