Question

2-(50) Find Is, Ic IVCE and the region of operation IM2 20012 2 200

Answer 1

3V 10 kn {0.2k IB+ Ic IB Ic B=200 + UBE ein Assume this is working Active region. VB <VE Cutt off segion VCE 70.28 Active region Saturation sgin VCE LO.2V VBE COND= 0.7V VE=ov UB=0.7V VB >VE SO not in cutt oft region Apply KvL in the dotted path 3=0,2 (IB+ Ic) + 10 IB + VBE O 3 Ic= BIB= 20018

3 2-3= 3-0.7= 0.2 IB + 0.2 8 IB + 10 IB IB (0.2 + 40 + 103) IB= 2.3 1040.2 IB = = 2.21 X10 2.21X163 6 А LB = 2.21 MA Icz ß TB B = 200 Ic= 200 x 2.21 x 100 Ic= 0.44 MA VCE = Vc-VE = vc-o=Vc. VC= 3- Rc (Ic +IB) = 3 + 0.2 (2. 20X10 +0.44) Vc = 2.91 VCE=Vc = 2.91 [VCE = 2.91N VE > 0, 2v (vat) So our Assumptions are Correct This is working in Active region

This is working ein Active region IB= 2.21 MA LC = 0.44 mA VCE = 2.910