Question

2.-(50) End Is, ICVCE and the region of operation, 20012 IM AW 3v 62 200

Answer 1

Solution Given Circuit IE (M. 2001 + B=200 3v YIC KUL equation IB 3- 200 IE 106 113 -0.7=0 Assuming it is Active region -) 2-3 - 200 (BH) IB + 10% IB 2.3 - 6 IB - 2.214A, IB 2.214A 106+ 200 201 so TE = (BH) Ir = 444-214A Fe = 442 MA

Voltage at nodes, E, B and c Vc = 3 - Pe x200 = 3 - 200x 444-21 x10-6 Vc = 2-911 volt VE こOV VB = Hence VBE =Ve- Imax Ig = 2-911 - 106x 2.21x10-6 0.701 volt = 0.701 Vott (forward bras) Vn = 2:11 o 701 = 2.20 (reverse bias) our asrumphon is connect 2.2144 442 44 = 2.9117 so In = Ic VCE