Question

The mechanical component shown in the diagram is 200 mm wide and 10 mm thick and is made of aluminum that has a yield stress of 240 MPa. Calculate the maximum safe load P that can be applied if the normal stress in the component must not exceed the material’s yield stress. Include a factor of safety of 3.50 mm 100 mm 80 mm 25-mm radius (typical) 50 mm

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Answer #1

S, = 240 MPa Maximum stress in the component, F max max Amin = Р (200 - 100)x10 max P 1 = P mm? Minimum stress in the componeFOS = 3 The yield factor for safety S. o max N 240 3= mm 1 P mm P=80N

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