Question

When an object falls in Earth's gravitational field (think of a skydiver jumping from an airplane or a marble falling in a tank of oil), it accelerates due to the force of gravity. If gravity were the only force acting on the object, then all objects-elephants and feathers alike would fall at the same rate. But gravity is not the only force present. Moving objects also experience resistance or friction from the surrounding medium; it would be air resistance for a skydiver and fluid resistance for a marble falling in oil. The strength of the resistance depends on several factors, among them the shape of the object and the thickness (or viscosity) of the surrounding medium. The effect of resistance is that a falling object does not accelerate forever, as it would without resistance. Eventually the gravitational force acting downward and the resistance force acting upward balance each other. As this balance is reached, the object approaches a constant terminal velocity. 

The motion of moving objects is described by Newton's second law of motion, which says that Mass x acceleration = sum of external forces. 

For a falling object there are two significant external forces: gravity and resistance. We let 2(1) be the position of the falling object where x = 0 is the point at which the object is released and the positive direction is downward (Figure 1). 

Answer 1

1) kg per second

2) v(t) = mg/k( 1- exp(-kt/m))

3) V_{​​​​T}are 9.8m/s( k=.1) ,1.96 (k=.5) and for k=1 it's .98 m/sec

4) terminal Velocity = mg/k and terminal velocity is inversely proportional to k

5) kg per metre

6) it's a prove that
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All graphs should be like g amg k for k= Ool Vp is than to times more for case kal 9.8 mis •Kzool 1.96 6.98 + Keo.5 K= 4.0 Time V = mg K Vt inversely proportional to к 5) R2 kV² R kg m/? kg (kg per metre m 6) du a²_v² kt a² 2 mg m K D Standard are tan integral! V V-a 2 kt 29 Vta m kg t V-mg e V-a zakt Vta cross multiply to get answer. vt jmg/k