Q5
a.
pH = -log[H+]
pH = 12.76
12.76 = -log[H+]
log[H+] = -12.76
[H+] = 10^(-12.76) M
= 1.738*10^-13 M
b.
For ionic product of water Kw = [H+][OH-]
Kw = 10^-14
[H+] = 1.738*10^-13 M
10^-14 = [H+][OH-]
10^-14 = (1.738*10^-13)[OH-]
[OH-] = 10^-14/(1.738*10^-13) M
[OH-] = 5.754*10^-2 M
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