Question

There is a new not technique for touch screen devices that allows users to mout a word by siding a finger from letler to ieter. The user's finger is only removed from the keyboard between words. The accompanying data table shows the typing spends of 10 individuals who were measured typing using both methods. Complete parts (8) through (di below m Click the icon to view the datatable 1. Pertom a hypothesis heet usinge -0.05 to determine if the average typing speed using these two hput methods is diferent. Let yiy be the population mean of maisted pair differences for the typing speed of the new method minus the typing speed of the traditional method. Choose the correct answer below OA HOW OBH NO Hy 0 OCH 50 M40 woberce no concite the song tong tpood for the two Iraut methode u ortoret Calculate the appropriate teststific and interpret the results of the hypothesis test using 0.05 The test state is Round to two decimal places as needed) The articles (ro) (Uwe ama to sagar answers as needed. Round to two cinales as needed) Interpret the results of the hypothesis lost Since the lost the calle hend hohese. There c. Identify the police and interpret the rest D-valle-Round to three decimal places as needed) Interpret the results of the hypothesis ostsing 006. Choose the correct we below O A Reject the nail hypothesis because the p-value is less than or equal to the given a 0.05 level. OB. Do not reject the null hypothesis because the p-value is less than or equal to the gen 0.05 level OC. Roect the rol hypothesis because the p-value is greater than the given 0.05 level OD. Do not reject the nuli hypothesis because the p-value is greater than the given a 0.05 level

Answer 1

lel, the given data as, Person New Traditional d = 1x1-x2|| Method X1 48 40 8 u 2 53 8 3 37 42 37 4 27 43 10 10 s 6 53 41 37 33 41 39 45 4 6 9 8 53 46 Lo 36 10 Totala 689 a) Testing the null & alternative hypothesis, Hoi Mdo Hold to where eld = Mn 'New . ll praditional x=0.05 b) The level of significance The test statistic is ta SI where sa= ( [d? (Eds? (Ed. 2) n-1

Calculator n=lo, cd = 69 {d²= 569 + .: d= {d 69 10 =) | J=6.9 n sá (569 - (69²) 10-1 92.9 9 10,3222 [Sd = 3.2128 ta Jio X 6.9 3.2128 2148197 3,2128 ta = 6.7914 Test statistic It= 6.79 &co.o5 & drag critical value of t at is critical t = 2,26 Interpretution Since the test statistic is greater than critical value, Reject the Null hypothesis. There is sufficient evidence to conclude that the average typeing speed for the hoo input methods is different

9) p-value = 0.000 ak 6.05 option (A) is comeel. Reject the null hypotheris because the P-value is less than or equal to the given a=0.05 level, dependent the d) The samples are disth of the matched-pair di Herences behoeen the measurements for the popn is approximately nomal if the no. of matched pairs is less than 30,