Question

What is the maximum power theorem. By analyzing the circuit given below, the maximum power theoreñ prove the definition with formulas (auxiliary way; Re the power of (Pc), he according to the derivative and Zero the result must be equalized.) RL www 4kn mm oku 12 mA 3ku 3v 3v

Answer 1

In Maximum Power theorem: any linear time invarient system the source can deliver the maximum power through the resistor RL when RL = Rth (thevenin's resistance) RL given circuit is b ч Кл Скл 2ma ЗКл + 3V Rh Rth Thevenin's resistance is the equivalent resistance between 'a' and 'b' where there is no source acting on it. Than cirant becomes Rth a گے ЧКл 6KA 3ka 3K2 & GK s are in parallel than result is 3x6 2Кл 3+6 The result ak12 is series to uku than 2+4=bkn Than Rth = 6kr By Maximum Power transfer theorem Remust be equal to ath to deliver maximum power so | RL=bkr CS Scanned with CamScanner

RL Auxiliary way: ukn V₂ Lкл given circuit is 2mA ЗКл 3V Let the nodes V, and ₂ as shown above Nodal Equation at node vi give - 3 2 X10 + 17-3 + V-v2 3 RL Hier x 10 - 3 Millet 3 2X10 + + V2 e che RL 4 x103 4X103 RL nodal Equation at node V2 gives V₂ VI V2 V2-3 of + 3 UX 103 3x10 6x103 265++) تعال 3 VI + 6 4 V2 = (2 + 4 4 4 4 3 Subtitute in eq@ than MC )+v2 (7)=2* = 2 + 3 when RL in 'ka' R2 + 2+ 3 láctý) +64 4 RL 2 t the-to) vil the 3+ RL 10 2014 vi 3 RL RL +0.2 A.V.A. Ram 34 2.IRL 0.2 RL+1 Power across Re resistor is = (1, -3) * R2 = (1,-3 )x RL (242541) - 3x RL 10.2 KLAI PL +(3+2+1 (3+21 RL-3-0.6R2 It o.2 RL ) = RL 15 R. PL 140.2RL To get maxium power ..PL than IRL Than we got RL=6k12 k. Lakit CS Scanned with CamScanner 20