Question

These are my measurements. This is for physics its a RC LAB. The purpose is that for a discharging capacitor we measure voltage and from this we determine the capacitance. Also from thee measured capacitance we can find thee internal resistance of the voltmeter

1)measurements over resistor

T(time every 10 seconds	Voltage(V)
1	5
2	4
3	2
4	1

—>The wanted us to plot In(v) vs time, and find the equation of the line.The equation of line for this graph is -0.1x+3. The measured resistance I found was 140 ohm.

Question 1: How do I use the equations and the resistance I found to calculate the actual capacitance?

2)Measurements over the voltmeter

T(eveery 10 sec)	Voltage (V)
1	5
2	5.5
3	4
4	3.5

—>I graphed V vs T, and thee equation of the line I found was (-8*10^-3)x +2

Questions 2: using equation of the trendline and also the actual capacitance that was found in the first question to find the resistance thee voltmeter

V = 5 V R = 150 k 22 + C = 470 uF + HH C = 470 uF (V Figure 4: Circuit for charging the capacitor. Figure 5: Circuit to measure voltage during discharge.

Answer 1

+/Rc (ear of dischassi 1) V = Voe en ve envo RC en vo=3 2 Vo = x3 en v z) 0 = 20.08 slope Rc >>>C: OLYR = 14 F -) 1: RC KUL 1140 -Vetur=0 =) UR = ve V um = VeXR Rt Rg -ERC. Rvo e R + Rs v(T) = -(8x103) +2. when complete discharge happen 2 &lt) At 10, VLT) = 2 PI 2) Ruo - 2 RtRg 2) RVO = 2R 2R, 2 R3 = Ro -2R = 1265.62 2