Question

3. An airplane flies 200, westward where Earth's 48 uT field points 28° North of down. The diagram shows the 40 m wingspan as viewed from behind (looking west). a) what magnetic force (vector!) is applied to an electron in the aluminum wing? 4 b) what voltage will accumulate along the wing? Show the positive side on diagram.

Answer 1

VIZ mill Airplane relocity = Magnetic field (B) Wing relocity = 200 m/s 48 UT 48x 10-6 T 0=28° with the The magnetic field makes downward directim.

In the direction perpendicular to the ring velocity vector, the sector component of the magnetic field has a magnetude of B 1 IB la casa 48x10-6 x cos 28' Bil = 42.3815 X10-6 T [ Directed perpendicularly down to the wing relocity (wing span ū ti

Charge of an electron - e 1.6X 10 С. Magnetic force Ť q . Ñ x 8 [Cross product q→ charge V> velocity B magnetic field perpendiculed For onor case I ū and Bis are - LF 1 = exlül x 1 Bul FI - =- [1-6x10-16 * 200* 42.3815X10-9] 1:356 X 10--21 N * The are sign indicates the direction of the force will be opposite from what we get in the right hand cross product rule Direction of Force rector from behing Clooking west) > = 1.356 X10-21 N

16 .. Length of the wing span - l = 40 m Accumulated voltage - 171 Bil x L E . 200 x 42:3815 X107" x 40 NE 0.34 Volt (Am As seen in the previous part, the force on elections left ward (if viewed from behind) are .: The left side will be ore charged. Wing from behind Am 6 If you have any confusion, ask me in the comments.