Question

sursework ZARA Create and Sha Adobe PDF Subtitle Title Abbcode bede Normal Аавьссос Аавьcераве Аавославьсераға No Spacing Heading 1 Heading 2 Styles Pane Question 20 During an experiment, a researcher was able to collect blood from different sizes of arterioles under a microscope. The data they recorded is presented in the Table below. Blood flow (Jul.sec" Time (S) 3.0 10 6.2 Diameter (um) Radius' (um) Volume (1) 100 6.250 x 10 30 5.80 36 11.5 1.296 x 10 120 3765 42 19.7 2401 x 10 140 244 48 4.096 x 10 160 The data was used to plot the relationship between and blood flow and the graph is shown below blood flow (sec-1) 2 (m) 10 What is the slope of the relationship? (using ul secum as units) (1 mark) the dus increases per mood tow also increases at an equal rate per sec

Answer 1

Answer-

According to the given question-

Here we have a graph between the radius of the arterioles and the blood flow, we have to find the slope of the graph.

We know that the

slope = Rise / Run = Y₂ - Y₁ / X₂ - X₁

Y₂ = 10 $\mu$ l / sec              

Y₁ = 5 $\mu$ l / sec

X₂ = 2 $\mu$ m⁴

X₁ = 1 $\mu$ m⁴

Slope = (10 - 5) $\mu$ l / sec / (2 - 1) $\mu$ m⁴ = 5 / 1 = 5 $\mu$ lsec^-1$\mu$m ^{- 4}

Slope = 5 $\mu$ lsec^-1$\mu$m ^{- 4}

intercept = c = ias defined as the point at which the line crosses Y-axis.

intercept = 2

15 Y2 blood flow (d.sec-1) 10 Slope = Y2- Y1/X2-X X1 < Y1 X2 Intercept = c = 2 (um) 10