Question

Chapter 3, Problem 3/037 The small 0.5-kg block slides with a small amount of friction on the circular path of radius 2.5 m in the vertical plane. If the speed of the block is 4.3 m/s as it passes point A and 3.1 m/s as it passes point B, determine the normal force exerted on the block by the surface at each of these two locations. 2.5 m B Answers: NA = Ng = Click if you would like to Show Work for this question: Open Show Work

Answer 1

sah 5 kg Mass Given that, of block (m) = 0.5 Radius of circular track (0) = 2.5m speed of block at a at a Ivo) = 4.3 m/s speed of block at a 2.5m |vs) = 3-1 omle

Efn - mva 0.5x4.32 Free body Tiagram at a my 2 my2 N-ng กาน NA mg + mg = 8.603 N

v free body diagram at B muz a v NR mg cosce mvh ng cosce of mva? 2. +0.5x3-12 Ang - NB 70 = 10.5 x 9.81 x 20 32 ) + NB = 4.1596 + 1.922 = 608162 " AL mga coso
friction act alone the horizontal axis. It doesn't affect the calculations.