Question

Section 2. Problem 6 (25 pts.) A hollow shaft 36 inches long tranmits 125 HP at 1100 rpm. The shaft is made out of steel with a modulus of rigidity of 11000 ksi. The shaft has an allowable sear stress of 12 ksi and an allowable angle of twist of 2.5 degreees over the 36 inche length. The inside diameter of the shaft is 0.6 that of the outside diameter of the shaft. Determine: a) the required inside and outside diameter of the shaft based on shear stress. b) the required inside and outside diameter of the shaft based on the angle of twist. (in.) [ (in.) Based on shear stress: Inside Diameter Outside Diameter Based on angle of twist Inside Diameter Outside Diameter (in.) (in.)

Answer 1

geben L=36 inch P= 125HP 125+7460 N = 1100 rpm L) 93250W wa 2an DU 21*1100 GO = 115.192 60 G=11000 kei 0=2.500 180 = 0.04 yarandi Zall = 12 kri 0.60o P = I xw P = .93250 115.192 =809.52 nom ~) 7.165 k-in a) zwein T rman J 12 2 7.166 x dol [24-(0.600 32 ot do 3 7. 165*32 24(1-064)+7 indy T do a 4.52 inch di = 0.91 b) Go J gy. 7.185*36 linio Go O=TL 0.044 z do=1.58inch di = 0.95 inch CS Scanned with SamScanner

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