Question

Hallo B I U a. Av obca v ili u A1 fx Amount B C D E F G 1 اهم الا Amount 2 20.50 3 14.63 23.77 29.96 6 29.49 7 32.70 8 9.20 9
► A1 x → fx Amount B с D E G А 12.03 34 25.53 35 27.71 36 33.81 37 21.79 38 19.16 39 26.35 40 20.01 41 26.85 42 13.63 43 17.2
Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in
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Answer #1

Given :

n = 64 , \sigma = 13

20.5 18.16 20.34 32.27 13.63 6.83 26.46
14.63 12.16 20.08 12.63 17.22 30.99 24.24
23.77 11.22 30.36 25.53 13.17 14.62 16.66
29.96 16.43 21.79 27.71 20.12 18.38 20.85
29.49 17.66 21.18 33.81 22.11 26.85
32.7 9.59 19.22 21.79 22.47 25.1
9.2 18.89 34.13 19.16 20.36 27.55
20.89 19.88 27.49 26.35 35.47 25.87
28.87 23.11 36.55 20.01 11.85 14.37
15.78 20.11 18.37 26.85 17.88 15.61

From the given values, the sample mean calculated is

\bar{x} = 21.52

\alpha = 0.01, \alpha /2 = 0.005

Hece the critical value of z will be,

z_{\alpha/2} = z_{0.005} = 2.58

Solution :

a)

At 99% confidence, the margin of error (E) is

E = z_{0.005}\frac{\sigma }{\sqrt{n}}

E = 2.58\frac{13 }{\sqrt{64}} = 4.19

At 99% confidence, the margin of error is $4.19.

b)

99% confidence interval can be calculated as

\bar{x} \pm z_{0.005}\frac{\sigma }{\sqrt{n}}

21.52 \pm 4.19

(17.33, 25.71)

99% confidence interval estimate of the mean amount spent for lunch is $17.33 to $25.71.


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