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Problem III. (12 points) Consider the following probability distribution. X 0 2 4 6 P(X = x) 1/4 1/4 1/4 1/4 1. (2 points) Fi

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Answer #1

1) E[X]=\sum x_iP(x_i)=0(\frac{1}{4})+2(\frac{1}{4})+4(\frac{1}{4})+6(\frac{1}{4})=3

2) There is a total of 6 sample of size 2 possible.

sampling distribution of the sample mean T for sample of size 2 is mean 3 and standard deviation 1.414

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