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Hydrogen peroxide (H202) decomposes according to the equation H2020) — H20(1) +202/9). Calculate Kp for this...
Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the following reaction equation 24,0,(aq) → 2H0(i) +0,(8) The activation energy for this reaction is 75 kJ. mol. The enzyme catalase (found in blood) lowers the activation energy to 8.0 kJ. mol-1 At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25°C? Number
Given the following equations and AH°: AH° (kJ/mol) -188 kJ Equation H2 + O2-H202 H2+1/202-H20 CS2 + 302-CO2 +2 SO2 -286 kJ -1077 kJ Calculate the value of AH° for this reaction: CS2 + 6H2O2 -> CO2 + 6H20 +2 SO2 0 -1551kJ 0-1665 kJ 0 -3921 kJ -1175 kJ
1. Calculate the quantity of heat released when 8.Sg of hydrogen peroxide decomposes, given: atomic weights 0=16, and H= 1. Hydrogen peroxide decomposes to water and oxygen according to the reaction: H = -196KJ 2. Given the speclflc heat, c,, of water Is 4.18 J/g 0c,how much heat Is needed to warm 200g of water from 22°c to 98°C? q=mC,AT 3. If 20.9KJ of heat were added to 250g of liquid water, how much would its temperature Increase? (Use 4.18 J/goc...