Question

A particular fruit's weights are normally distributed, with a mean of 431 grams and a standard...

A particular fruit's weights are normally distributed, with a mean of 431 grams and a standard deviation of 29 grams.

If you pick 10 fruit at random, what is the probability that their mean weight will be between 405 grams and 453 grams

P(405<¯x<453)=P(405<x¯<453)=

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Answer #1

M = 431 29 n-lo P (405 < x < 453) 0 6/405-4 453 - M +1 55 11 453 431 29/vo 405 431 29 1510 $ ( 2:34) • (- 2.84) 0.9904 - (1 -

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