Question

Test the claim that the mean GPA of Orange Coast students is significantly different than the mean GPA of Coastline students at the 0.02 significance level. The null and alternative hypothesis would be: ar H:HO MC H:Po <Pc H: Po = Pc H:MO HC Ho: Po PC H:Mo = MC H:HO > HC H: Po > PC H:Po + Pc H:HO MC H: Po Po H: Mo Mc o The test is: left-tailed two-tailed right-tailed O The sample consisted of 35 Orange Coast students, with a sample mean GPA of 3.27 and a standard deviation of 0.07, and 35 Coastline students, with a sample mean GPA of 3.3 and a standard deviation of 0.05. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis Check Answer

Answer 1

Answer we have given XL = GPA of Orange coast studen) m 35 XL = 3.27 Si= 0,07 X2= GPA of coastline student m2 = 35 Xe 3,3 S2 = 0.05 Q=0. 02 Now cue have to test Ho : Hui Mo= Mc Mo # Mc Test df= Test is two tailed. nit n, - 2 = 35 + 35- statistic becomes 2 =68 ts - X2 (1,-1)5² + (92-1)S? nitha-2 thit b) = 3.-27 3.3 (35-12 0.0722+ C35-1) Drog? (bus te as B5+35-2 te 2.063 Test Test statistic -2.06 tail elf का p- Value =_TPISIC 2.061 68, 3) = 0.04 p- Value 0.041 R- value a fail to Reject null hypothesis