Question

using mesh analysis method

Whe Find the transfer function output for the electrical circuit below input 2H 2221F 0000 222 22 222 v(t) 232 + vo 21 VLt) 1F 2H WE 0000 llll VL(1) (a) (b)

Answer 1

Find the transfer function output ofor the page! input electrical cruit below. 2H mo a 22 22 + Vlt) Leulu un + 2H ville) into solution - Above electrical circuit converted s-domain 25 m 32212 212 + + vis 1,6) 176) 325 v (s) Applying KvL in mesh (01) -V15) +230,($)+2(1,6) - L2(59] r(s) +251 (s) + 2 (S) - 2 I ₂ (S) = 0 (25+2) 4(5) — 21265) = V() - ) Applying KvL in mesh (02) 2. T() +25120) +2 (10)-46)] = 0 2.126) f 2512(3)+2126) - 21(5)=0 4 Iz(8) + 25 Izf) - 25 (B) = 0

from equation (i) and (ii) -276) + (4 +25)1,0) = 0 -ü) page2 (25+2) L(S) - 2/3 (5) = V(S) X 2 - 2 L(S) +(25+4) ()= 0 X (25+2) (45+4) 66 ) – 41,(3) = 2V(S) -2625127 - 2(25+27 052 + 25+4) (2642) 1262-0 - 41,01) + (25+4) (25+2) 16) = 2V) &I () + (45²7 45 +85 +8] 12()=21 2v (3) - 41,66 +452+125+*] 1,0) = 2V(5) 1,0)| -4 44 4448°412548] - 2r(1) 126) [ 4s +125 + 4) = 2V(8) Iz (S) 2 r(s) 41²412544 2 V(s) I 2(1) = 4 (5²+ 12 5+1) F I(S) = 0.5v(s) (3²435+1)

say that pages As per Electrical circuit we can Voltage across inductor is equal to VL(S) = 25 [21] ~ (S) = 25T 0.5V) s2435+1 VL (S) = SV (1) 2 S²+35t I VD sves) r2+35+) *** S Output ve (6) 3²+35+1 input 6 solusion min! 212 322 f + 24 Velt) VIO Abore Electrical circuit converted into sodomain

- QI(S) - 4B) + 4I. (S) + 25 [g(S) + I (S). (Page 8 21 :20 8212 vs) I, (S) I(S) 25 elle r(s) Applying KrL in mesh (61) v(s) +2 I (6) + + I (S) + +2[46-160] ++ [17 VS2 +245) +5465)+24 (5) — 21268) + I(S) - [26] S ک - 6 s VS) + 440) +1(32 +150)-25, (1) – 10 = vG) + (4 + 3) 465) (2+4)1,6)=0 ( 4+ 5)2() - 6+1)1,0) = V0) 0 kvL in mesh (02) [1-6)-5102] + 2340)+255,91+(50-560)) = 2 I (S) – 26(1) +855) + 255/5) + 123). LOW- Applying - o s s - O s -(2+4)16) +(4+25+) 10) = 0

page solving equation 6 and equations ( theon we get (4+ 3)40 ) - (2+4) 1,60 = v) * (245) - (2+}) }(6) + (4725+) 28)=0 (012) (4+})(2+1) 7 () 6+)(244) 50 ) = (2+1) vo -4}) (43)|() +(4+25+4)(4+3)16) = 0 -(4+1/2+2. 2. 3) + (16+ 25x4 + 1 x 4 + 4x2 + 2x xx 2 + + x 2) 1,659 = (2+1)vis) (-1*83** (***) (*2)) 7,0) = 673) ) (---)- [-f-2/ 1,0) = (***) vo ****4].5.0 - (41) +4+3 +4 + 3] 1, 0) =(es) Vos +16+85t + 1678578 S 2 - 1 J2 [ (2 us) I 52

Page 6 1 + 165² +8585² +85 I 2 (B) = [ 100 metres) (est) vi ) 1+165² +85² +85 I 2 (S) = OVO *** 10%) = (25+1) VS) [ 854161** ***' J 1,0) = (2+1) I20) = s(2841) ves) 853 +1652+$5+1 As per theatrical çocent que cam say that voltage Alross induites is equal to . (S) = 25 I 2 (8) v(s) V (B) = 25 S(25+1) 853+1652+85+1 418- Vers) output 25² (241) 853 +1652485+1 imput VG) 453 +252 853 +165²+8+ | (15) ris) Final Answer