Question

Intensity Frequency 1 450 2 510 3 213 4 98 5 46 1317 Total Find the mean intensity number: Oa 2 Ob. 2.07 Oc. 3 Od. 546.20 19.

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Answer #1

Question 18) -

We find the mean number by using the following formula,

mean=\frac{\sum x_if_i}{\sum f_i}

x_i is the ith intensity and fi is the frequency if ith intensity

Intensity (x_i) Frequency (fi) x_ifi
1 450 450
2 510 1020
3 213 639
4 98 392
5 46 230
Total 1317 2731

Mean = 2731 / 1317 = 2.0736

Hence, correct option for mean intensity number is 2.07

Question 19) -

Let X denote the test score

It is given that X follows bell shaped (normal) distribution with mean \mu = 80 and standard deviation \sigma = 6

Z=\frac{X-\mu}{\sigma} follows standard normal distribution.

We need to find interval (a,b) such that P[ a<X<b ] = 0.95

P[\frac{a-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{b-\mu}{\sigma}]=0.95

Probability outside the interval is 0.05. Hence, probability below lower limit is 0.025 and above upper limit is 0.025.

That is, P[\frac{X-\mu}{\sigma}<\frac{b-\mu}{\sigma}]=0.975 and P[\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma}]=0.025

From the standard normal probability tables we have that,

P[ Z < -1.96 ] = 0.025 and P[ Z < 1.96 ] = 0.975

Hence, \frac{a-\mu}{\sigma}=-1.96\Rightarrow a=\mu-1.96\sigma=68

\frac{b-\mu}{\sigma}=1.96\Rightarrow b=\mu+1.96\sigma=92

Hence, an interval in which 95% of the scores fall is ( 68, 92 )

Question 20) -

According to the definition Median M is defined as the point below which 50% of the observations lies and above which rest of the 50% of the observations lie.

That is, P[ X < M ] = P[ X > M ] = 50% = 0.5

Hence, The statistic that describes the fiftieth percentile in a sample is known as Median.

I hope you find the solution helpful. If you have any doubt then feel free to ask in the comment section.

Please do not forget to vote the answer.

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