Solution -:
Q(1)
By using R-Software:
> #(1)P(F>0)
> p1=1-pf(0,51,5);p1
[1] 1
> #P(F>0) not < 0.5 It is not true statement
> #(2)P(F>2.5)
> p2=1-pf(2.5,51,5);p2
[1] 0.153442
> # P(F>2.5) > 0 It is true statement
> #(3)P(F<10000)
> p3=pf(10000,51,5);p3
[1] 1
> #P(F<10000) <= 1 It is true statement
> #(4)P(F>300111222)
> p4=1-pf(300111222,51,5);p4
[1] 0
> #P(F>300111222) >= 0 It is true statement
Ans : 1 is correct
R-Code:
#(1)P(F>0)
p1=1-pf(0,51,5);p1
#P(F>0) not < 0.5 It is not true statement
#(2)P(F>2.5)
p2=1-pf(2.5,51,5);p2
# P(F>2.5) > 0 It is true statement
#(3)P(F<10000)
p3=pf(10000,51,5);p3
#P(F<10000) <= 1 It is true statement
#(4)P(F>300111222)
p4=1-pf(300111222,51,5);p4
#P(F>300111222) >= 0 It is true statement
Q(2) Ans : 1 is correct
question 1 question 2 Suppose F follows an F distribution with 51 and 5 degrees of...
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