1. Suppose t hat Xhas t he chi-square distribution on p1∈(0, ∞) degrees of f reedom and that, i ndependently, Y has t he chi-square distribution on p2∈(0, p1) degrees of f ree-dom. a. Use moment generating functions to find the distribution of X + Y . b. A naive guess might be that the distribution of X − Y is chi-square on p1− p2 degrees of freedom. Prove that such a guess is wrong by demonstrating that P (X − Y < 0) > 0, whereas a chi-square random variable cannot take on negative values. (i) First show that P(X < 1, Y > 1) > 0. You may quote without proof the well-known fact that the integral of a nonnegative continuous function over an interval of nonzero length can only equal zero if the function itself is identically equal to zero. (ii) Then show that P (X < 1, Y > 1) > 0 implies P (X − Y < 0) > 0. c. Use the one-to-one bivariate transformation formula to find the joint distribution of U := X + Y and V := X − Y .
1. Suppose t hat Xhas t he chi-square distribution on p1∈(0, ∞) degrees of f reedom...
10) Suppose that X follows a chi-square distribution with m degrees of freedom and S=X+Y. Given that S follows a chi-square distribution with m+n degrees of freedom, and X and Y are independent, show that y follows a chi-square distribution with n degrees of freedom.
The shape of which distribution is not controlled by the degrees of freedom? F t Which of the following accurately represents characteristics of the x2 distribution? There may be more than one correct answer, select all that are correct. The degrees of freedom for a Chi-square test of independence are k-1. As the degrees of freedom increase, the critical value of the chi-square distribution becomes larger. | It can assume both negative and positive values. The Chi-square goodness-of-fit test is...
proof for distribution of (n-1)S^2/sigma^2 is the chi square distribution with n-1 degrees of freedom. I don't understand the expansion of the square, specifically how certain terms disappeared and how a sqrt(n) appeared. Also towards the end, why does V have a degree of freedom of 1? x A detailed explanation of what happened from step 2 to step 3 would be very helpful! THEOREM B The distribution of (n − 1)S2/02 is the chi-square distribution with n – 1...
Let X1,... , Xn be a random sample from the Pareto distribution with pdf Ox (0+1), x > 1, f(z0) where 0>0 is unknown (a) Find a confidence interval for 0 with confidence coefficient 1-a by pivoting a ran- dom variable based on T = T log Xi. (Use quantiles of chi-square distributions to express the confidence interval and use equal-tail confidence interval (b) Find a confidence interval for 0 with confidence coefficient 1 - a by pivoting the cdf...
Let X1,... , Xn be a random sample from the Pareto distribution with pdf { f (r0)= 0, where 0>0 is unknown (a) Find a uniformly most powerful (UMP) test of size a for testing Ho 0< 0 versus where 0o>0 is a fixed real number. (Use quantiles of chi-square distributions to express the test) (b) Find a confidence interval for 0 with confidence coefficient 1-a by pivoting a ran- dom variable based on T = log Xi. (Use quantiles...
2. The chi-square distribution plays a significant role in performing inference on the as- sociation between categorical random variables (e.g., car injury severity and seat belt usage). If Z ~ N(0,1), then W = Z2 ~ xỉ – that is, W has a chi-square distribution with 1 degree of freedom. Furthermore if Z1, Z2, ..., Zn N(0,1), then W = Z+Z2+...+22 has a chi-square distribution with n degrees of freedom. Here are some helpful facts. Let t > 0 •...
question 1 question 2 Suppose F follows an F distribution with 51 and 5 degrees of freedom. One of the statements below is false. Enter the number of the false statement. 1. P(F>O) <.5 2. P(F>2.5) > 0 3. P(F<10,000) < 1 4.P(F>300,111,222) > 0 Suppose a variable of a population follows a Chi-Square distribution with 46 degrees of freedom. I take 791 samples of this variable from the population, and compute the mean for each sample. If I were...
4. Let 8 >0. Let X, X2,..., X, be a random sample from the distribution with probability density function S(*;ð) - ma t?e-vor x>0, zero otherwise. Recall: W=vX has Gamma( a -6, 0-ta) distribution. Y=ZVX; = Z W; has a Gamma ( a =6n, = ta) distribution. i=1 E(Xk) - I( 2k+6) 120 ok k>-3. 42 S. A method of moments estimator of 8 is 42.n 8 = h) Suggest a confidence interval for 8 with (1 - 0) 100%...
1. Suppose (x, Y) has bivariate normal distribution, E(x) E(Y)- 0, Var(X) σ , Var(Y) σ and Correl(X, Y) p. Calculate the conditional expectation E(X2|Y).
Which of the following is not a characteristic of the chi-square distribution? Select all correct answers. Select all that apply: The chi-square curve is symmetrical. The chi-square curve is skewed to the left. The total area under the χ2-curve is equal to the degrees of freedom, df. The total area under the χ2-curve is equal to 1. Does buying CDs depend on whether you own a smartphone or not? A survey asks a group of students if they buy CDs...