Question

Consider a situation where we want to compare means, M1 and 42 of two populations, Group 1 and Group 2, respectively. A random sample of 40 observations was selected from each of the two populations. The following table shows the two-sample t test results at a = 5% assuming equal population variances: t-Test: Two-Sample Assuming Equal Variances Group 2 28652 33.460 40 Mean Variance Observations Pooled Variance Hypothesized Mean Difference d t Stat PTcut) one-tail Critical one-tail PTC-t) two-tail Critical two-tail Group 1 30.130 72 828 40 53.144 0 78 0907 0.184 1665 0.367 1.991 Consider the following two tests: Test A Ho:#11 - M2 = 0, H.: 11 - 12 #0 Test B Ho: #1 - 3 = 0, H:11-13 > 0 1. The P-value for Test A Choose 2. Conclusion of Test A Choose) 3. The decision rule for Test B [Choose 4. Conclusion of Test B [Choose 5. A point estimate for the difference between the two population means [Choose 6. The standard error of the difference between the two sample means [Choose

Answer 1

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1. The P-value for test Hourl=0, Hau, esto is equal to P(Tet) two tail that is 10.367 which is more than 0.05 no We fail to reject. the voll hypothesis and conclude there is evidence, since povalue is greater than significance level. are diffenent. that 2 means 3. Critical value for testing hypother's test-B. • 0.907 C-tstat) (p(est) onetail) is and IP value = 0.184 4. We reject the vull hypothesis and conclude that meer since the test statistic is less than critical value. 4 - - 30.130 - 28.652 > 0 5. point estimate estimate for the diffeuence between the two population means is Mill 30.130 - 28.652 1.478 6 standard error is Spooled variance [53.144 = 7.29

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