Question

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (b) below. Tin (13.046, 22.15) X 17.500 Sx 16.01712719 50 2. Express the confidence interval in the format that the less than symbol. Given that the original led data use one decimal place, round the confidence interval limits accordingly Mbps <<Mtos (Round to two decimal places as needed.) b. Identify the best point estimate of and the margin of error The point estimate of pils Mops (Round to two decimal places as needed) The margin of error is E-Mbps (Round to two decimal places as needed)

Answer 1

Solution : We have given that i confidence interval is (13.048, 22.15) ii) sample mean = 17.598 Sample Standard deviahon iv) Sample size : 50 ili) Sy 16.01712719 n = confidence interval in the format uses “less than forme a) Express the symbol kle have given the interval * 2 Rounding this to (13.048 22.15) one decimal place (13.0 , 22.2) © . Thus, Mbps 13.0 Mbps <H < 22. 2 - of essor margin b) 1 dentify best point estimate of li and The confidence interval for el is (3 - margin of error mangin or) : Exi sample mean = 17.598 -. given → - 17.60 rounded to a decimal of essor x+ - nie

ego and Now comparing , we get Š - margin of emor 13.048 y + margin substract eg" @ from ® , we have (morgon of error) in of esmor : 22.15 ♡ 2 * 22.15 - 13.048 → margin of esson 9.102 2 margin of enor 4.551 margin of emor = 4.55 rounded to 2 decimal Result: a) 13.0 Mbps < el < 22,2 < 22.2 Mbps b) i) point estimate of el : 17.60 11) Margin of emon 4.55 ( +