Question

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. Tinterval (13.046,22.15) x= 17.598 Sx = 16.01712719 n=50 a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly. Mbps <u<Mbps (Round to two decimal places as needed.) b. Identify the best point estimate of u and the margin of error. The point estimate of u isMbps. (Round to two decimal places as needed.) The margin of error is E-Mbps. (Round to two decimal places as needed.) c. In constructing the confidence interval estimate of p, why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution? O A. Because the sample size of 50 is greater than 30, the distribution of sample means can be treated as a normal distribution Rarance the eamnle standard deviation le nown the normal dictrihistian ran ho reor in rannart the ronfidence Click to select your ansieri

Answer 1

Given Confidence Juterval (13.046, 22:15) Mean = 17.598 Standard devation 16.01712 Sample Size = 50 FE17.598 Si=16.017 n=50 Cal is 13°05 až <22-15 a) The Col in the format that uses the less then bol is 13.05< Ž < 22-15 b)Point estimate for the population mean is sample mean itself M = sł =) 17.598 6) The Margin of Error is lower linit ă-ME 13.046 = 12,598 – ME ME = 4.552 c) option CS Scanned with CamScanner