If z is standard normal variable, find the probability. The probability that z lies between -1.25...
If z is a standard normal variable, find the probability. The probability that z lies between 0.7 and 1.98 0.2175 0.2181 -0.2181 1.7341
If z is a standard normal variable, find the probability that z lies between -2.14 and 0. Group of answer choices a) 0.9820 b) 0.4391 c) 0.4920 d) 0.4838
if 2 is a standard normal variable, find the probability that lies between -2.41 and 0. Round to four decimal places. O A. 0.5080 OB. 0.0948 OC. 0.4920 OD. 04910
Determine the area under the standard normal curve that lies between (a) Z= - 1.17 and Z = 1.17, (b) Z= -2.68 and Z= 0, and (c) Z= 1.09 and Z= 1.25.Click the icon to view a table of areas under the normal curve. (a) The area that lies between Z= - 1.17 and Z= 1.17 is _______ (Round to four decimal places as needed.)
QUESTION 10 4 If Z is a standard normal random variable, then P(-1.25<= Z <=-0.75) is QUESTION 11 4F It is given that x, the unsupported stem diameter of a sunflower plant, is normally distributed with population mean mu=35 and population standard deviation sigma=3. What is the probability that a sunflower plant will have a basal diameter of more than 40 mm? 4 pc QUESTION 12 A random variable x is normally distributed with u = 100 and o-20, What...
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(z ≤ −0.11) = P(z ≥ 1.25) = P(−1.17 ≤ z ≤ 2.44) = P(0 ≤ z ≤ 1.65) =
4. Let Z ~ N(0,1) be a standard normal variable. Calculate the probability (a) P(1 <Z < 2). (b) P(-0.25 < < < 0.8). (c) P(Z = 0). (d) P(Z > -1).
Find z such that 9% of the area under the standard normal curve lies to the right of z. Find z such that 58% of the standard normal curve lies between -z and z. Future Electronics makes compact disc players. Its research department found that the life of the laser beam device is normally distributed, w 470 hours. (a) Find the probability that the laser beam device will wear out in 5000 hours or less.
Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Round your answers to four decimal places.) (a) P(0 ≤ Z ≤ 2.64) (b) P(0 ≤ Z ≤ 2) .4772 Correct: Your answer is correct. (c) P(−2.10 ≤ Z ≤ 0) (d) P(−2.10 ≤ Z ≤ 2.10) (e) P(Z ≤ 1.94) (f) P(−1.45 ≤ Z) (g) P(−1.10 ≤ Z ≤ 2.00) (h) P(1.94 ≤ Z ≤ 2.50) (i) P(1.10 ≤ Z) (j) P(|Z|...
if z is a standard normal variable find the probability that (p(-0.73) < z <2.27 If z is a standard normal variable find the probability that p(z < 2.01)