C) The process was irreversible.
Since, ∆Ssys<0, the closed system experiences an irreversible process with the reverse process is spontaneous.
When ΔS < 0 and ΔH > 0, the process is never spontaneous, but the reverse process is always spontaneous.
QUESTION 4 A closed system experiences a process such that ASsys< 0. From this information, we...
Explain the answer A closed system experiences a process such that ΔSsys< 0. From this information, we can conclude: The process was isothermal. The process was non-adiabatic. The process was irreversible. The process was impossible.
54. During a spontaneous chemical reaction, it is found that ASsys < 0. This means a. AS surt < 0 and its magnitude is < ASsys. b. AS sur < 0 and its magnitude is > ASsys. AS surr > 0 and its magnitude is < ASsys. ASgurr > 0 and its magnitude is > ASsys. an error has been made, because Ssys > 0 by necessity for a spontaneous process.
Please answer all questions, I will upvote thanks. QUESTION 1 Which of the following statements about entropy is false? Entropy is a measure of molecular disorder. Entropy is a property and process path independent. Entropy is always generated during a process, including in a Carnot cycle. Entropy can decrease during a process. QUESTION 2 Which of the following statements about a reversible process is false? Reversible process is an idealized process that has no irreversibility involved. Work-consuming device consumes the...
Prove the statement is true. (b) Qn(0, 0) <RR
Question 4 2 pts Find P(-1.47< z< 1.79) = places. Round to 4 decimal
7) An ideal gas is taken around the cycle shown in this p-V diagram, from a to b to c and back to a. Process b-c is isothermal. For process a- b, D. 0-0, AU<0 8) An ideal gas is compressed in a well-insulated chamber using a well-insulated piston. This process IS A) isochoric. B) isothermal. C) adiabatic. D) isobaric. 9) The process shown in the T-V diagram in the figure is an T. A) adiabatic compression. B) isothermal compression....
Question 2 2 pt Find P(z<2.35)= Round to 4 decimal places.
Question 4 < > Solve the initial value problem below. xʻy" – xy' +y = 0, y(1) = – 5, y'(1) = 0 =
- 2 + x - 2 < 0 has no solutions. True False
Solve the inequality 22 +2 - 2 22 - 5.0 + 6 <0