Question

Explain the answer

A closed system experiences a process such that ΔSsys< 0. From this information, we can conclude:

		The process was isothermal.
		The process was non-adiabatic.
		The process was irreversible.
		The process was impossible.

Answer 1

∆Ssys<0 implies that system is non spontaneous but we can't say that system is impossible.

If the process is irreversible then it's spontaneous which is not the case here

Now ∆S=dQ/T

So ∆S<0 implies dQ/T<0

Therefore dQ<0

And for adeabatic process dQ=0( no heat transfer)

So this process is non adeabatic

And we can't cay anything about temperature wether it's constant or varying

So it's not isothermal process

Correct answer-B) the process was non- adeabatic.