Question

A genetic experiment involving peas yielded one sample of offspring consisting of 426 green peas and 134 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.25 O B. Ho:p*0.25 Hp+0.25 H:p>0.25 0 C. Ho: p = 0.25 OD. Ho: p=0.25 H:p> 0.25 He: p=0.25 O E. Ho: P+0.25 0F. Họ p= 0.25 HP<0.25 H: P<0.25 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.)

Answer 1

Sol Que-1 n= 4 26 + 134 =560 ca) P option (A) H: Hai = 0.25 P & 0.25 Ob) What is the test statistics. re -P sla 134 = 0.24 426+134 Z = P(1-0 0.24-0.25 0.85 (1-0.25) 560 -0.59 P-value 0.555 P(z=-0.59) Do not Reject Ho Due to HomeworkLib policy, I home to attempt first Question Thank you. CS Scanner with CamShannon