Solution :
This is the two tailed test .
The null and alternative hypothesis is
H0 : p = 0.25
Ha : p 0.25
n = green peas 434 + yellow peas 180 = 614
x = yellow peas =180
= x / n = 180 / 614 =0.29
P0 = 0.25
1 - P0 = 1-0.25 = 0.75
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.29 - 0.25/ [(0.25*0.75) / 614]
= 2.29
Test statistic = z =2.29
P(z > 2.29 ) = 1 - P(z < 2.29 ) = 1 -0.9890
P-value = 2 *0.0110 =0.0220
= 0.01
P-value >
0.0220 > 0.01
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that
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