Question

20 point the feed to determine the reaction at the supports, drew the show and moment diam. Assume A is fixed and is a roller. El is constant the shear and moment diagrams on your hand call sheet Loading 1 + Equation + PL ЗЕ/ at x2 0.. = PL 2ET - GET (2 – 3Lx?) at x L L MacBook Air A

Answer 1

Complete solution is given below.

Solution : ISK A ܠ e lol lol 1) DOI = 4-3 =) Assume reaction at B as redundant to primary stinctive is, ISK B ܠܠܠ e 10! ey Generate (Aa] 15 x 10 = 150 k-ft MA io d' ro! & B A conjugate beam M diagram EL 150 EL BM@ BY AL > Deflection af B X 10 x 150 eІ :) [i 10+ fx10] (42] = 12500 ET

37 Generate flexibil ty matrix Apply on't coad at redundant , - Assome RB acts in the direction of load. 11 10 C ܠܠܠ MA (x20 = 20 اح 20 BM @ B! (8) - (* x 20 x cm) * ( $x 20) (6) 2666.67 EI Appay flexibility equation [p] = {FJ (+) { [A] - [AL]} EI (2666.67] [FIRE RB x

{Ro = -406875 K > Negative sign indicates opposite direction to loads. RB = 4.6875K Acting upwards. Efy=0 Mc = (10.3125x10) RA + RB = Mc = 'RA = 10.3125 K . -56.25 ISK 46.875K8 MA =-(15*10) + ( 406875 x 20) (MA =-56.25 kott 10.3125 SFD с A 4.6875 K 46.875 k-ft * -B BmD 56.25kft