Question

Based on the Punnett square, what is the probability a child will have a widows peak, an autosomal dominant phenotype? A a A

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Answer #1

Answer: 75%

Explanation:

In an autosomal dominant inheritance, only one copy of the dominant allele is required to express the phenotype of the dominant allele.

Here, AA is homozygous dominant, Aa is heterozygous dominant and aa is homozygous recessive. In the genotypes of the offspring given in punnet square, only 'aa' will exhibit the phenotype of the recessive allele 'a' and all the other offspring has at least one dominant allele, hence, expresses the dominant phenotype (widow's peak). Therefore 3 out of four offspring express widow's peak hairline, so the probability of the child having widow's peak is 75%.

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