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2. For this series of 4 questions, a man sits in the chair which is pin-connected to the 10-m frame BC. Frame BC rotates counFn = Nn – m: 9.81 · sin 30º = 0 ΟΣF = N, m. 9.81 · cos 30° = m. at OFt = Né – m: 9.81 · cos 30º = 0 OFn = Nn + m - 9.81 · sin

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Answer #1

Solution diagram Free badly of man 2 Nt Nn my 330 D EFL= N - m.9.81. (of 30° m. at \/ t E Fn = Nn m.9.8). Sin 30° = mian CSSc

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