Is there a difference among the 3 treatments in the table below? Test using α = .05 Complete the ANOVA table that follows as an aid (Recommend doing so on a separate sheet of paper, or separate document), then answer the questions that follow.
Treatment A | Treatment B | Treatment C | |
0 | 2 | 4 | ∑X2 = 114 |
0 | 3 | 2 | G = 36 |
0 | 1 | 4 | N = 18 |
3 | 3 | 3 | k = 3 |
0 | 2 | 4 | |
0 | 1 | 4 | |
SS1 = 7.5 | SS2 = 4 | SS3 = 3.5 |
Source Sums of Squares df Mean Square F
Between SSbn dfbn MSbn F
Within SSwn dfwn MSwn
Total SStot
SStot =______ SSwn = ______ SSbn = ______
SStot =114; SSwn = 15; SSbn = 99
SStot =42; SSwn = 12; SSbn = 30
SStot =42; SSwn = 15; SSbn = 27
SStot =114; SSwn = 24; SSbn = 90
[example continued...]
Is there a difference among the 3 treatments in the table below? Test using α = .05
dfwn = ______ dfbn = ______
dfwn = 17; dfbn = 2
dfwn = 2; dfbn = 17
dfwn = 15; dfbn = 2
dfwn = 2; dfbn = 15
MSbn = ______ MSwn = ______
MSbn = 13.5; MSwn = 1
MSbn = 1.5; MSwn = 16
MSbn = 1; MSwn = 13.5
MSbn = 16; MSwn = 1.5
F = ______ (test statistic, F Ratio)
F = 1.00
F = 10.67
F = .094
F = 13.50
What is the value of the critical F boundary? (from the tables)
4.26
19.38
19.43
3.68
What is the correct result based on the data?
Reject Ho, result is Significant
Retain Ho, result is Significant
Retain Ho, result is NOT Significant
Reject Ho, result is NOT Significant
What type of error could you be making?
Type II
Type I
Does the type of treatment make a difference?
Yes
No
The correct APA format for the result would include
p < .05
p > .05
Is there a difference among the 3 treatments in the table below? Test using α =...
Is there a difference among the 3 treatments in the table below? Test using a - .05 Treatment A Treatment B Treatment C 0 2 4 EX2 - 114 G= 36 10 3 2 o 1 4 N = 18 3 3 3 k = 3 0 2 4 10 1 4 SS, = 7.5 SS2 - 4 SS3 - 3.5 dfwn dfon- Odfwn = 2; df - 15 Odfwn - 17; df = 2 dfun = 15; df =...
Treatment A Treatment B Treatment C 0 2 4 x2 = 114 0 3 G= 36 N o 1 4 N = 18 3 3 k=3 3 4 0 N 0 1 1 4 SS1 = 7.5 SS2 = 4 SS3 = 3.5 df F Source Between Within Total Sums of Squares SSbn SSwn Mean Square MSbn F dfon dfwn MSwn SStot SStot SSwn SSon SStot-114; SSwn - 15; SSbn = 99 SStot-42; SSwn = 15; SSbn - 27 Stot-42:...
Does training in study skills make a difference for student success? 8 students received training (M1= 85, SS1= 100) and 8 students did not (M2= 80, SS2= 124). Test using α = .05 Which is the null hypothesis, H0? µ1 = 0 µ1- µ2 ≠ 0 µ1- µ2 = 0 µ1 ≠ 0 The degrees of freedom (total) (df) = 18 14 16 10 With alpha = .05, (two tail, nondirectional test), the critical t score boundaries = +/- 2.145...
For either independent-measures or repeated-measures designs comparing two treatments, the mean difference can be evaluated with either at test or an ANOVA. The two tests are related by the equation F=12. The following data are from a repeated-measures study: Person Difference Scores 3 I 4 2 3 7 M = 4.00 T = 16 SS = 14 Treatment II 7 11 6 10 M 8.50 T-34 SS = 17 3 3 Mo 4.50 SS = 27.00 Use a repeated-measures t...
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ANOVA F-test revealed mpare all 2. Consider randomized study with 5 treatments, A, B, C, D,...
(1) A psychologist would like to examine the relative effectiveness of 3 treatments for mild phobias. A sample of N=12 individuals who display a moderate fear of spiders is obtained. These individuals are randomly assigned (with n=4) to each of the 3 treatments. The dependent variable is a measure of reported fear of spiders after treatment. The data are as follows: (Treatment 1) 0 4 0 4 (Treatment 2) 1 5 4 2 (Treatment 3) 8 5 6 9 a....
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