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A manufacturer of flash drives has a profit function a = t - 3q2 where t is the price charged for a flash drive and q2 is the

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Answer #1

Ans)- Given Profit function-

Π = t – 3q2

Utility function, u = Øq – t

  1. For L-type consumer put Ø=8 in utility function

So, u = 8q – t

Since seller has complete information, the utility of consumer will be 0.

So,

u = 8q -t

put u=0

8q – t =0

qL = t/8 ---------    (1)

now profit function-

π = t – 3(t/8)2

Differentiate w.r.t. t

dπ/dt = 1 – 6t/64

put dπ/dt=0 [first order condition]

1 = 3t/32

[tL = 10.667] ------------------------------required profit-maximising value of ‘tL hat’.

Put t=10.667 in equation 1

[qL = 10.667/8 = 1.333 ]

  1. For H-type consumer put Ø=13 in utility function

So, u = 13q – t

Since seller has complete information, the utility of consumer will be 0.

So,

u = 13q -t

put u=0

13q – t =0

qH = t/13 ---------    (2)

now profit function-

π = t – 3(t/13)2

Differentiate w.r.t. t

dπ/dt = 1 – 6t/169

put dπ/dt=0 [first order condition]

1 = 6t/169

[tH = 28.166] ------------------------------required profit-maximising value of ‘tH hat’.

Put t=28.166 in equation 2

[qH = 28.166/13 = 2.166]

  1. Overall profit-

Π = t – 3q2

Put t = tH = 28.166

And q =qH =2.166

ΠH = 28.166 – 3(2.166)2

ΠH= 14.092 ----------------------profit from 1 H-type consumer.

Multiply by 10

Total profit from 10 H-type consumer = 10*14.092 = 140.92

Now, Put t = tL = 10.667

And q =qL =1.333

ΠL = 10.667 – 3(1.133)2

ΠL= 6.816 ----------------------profit from 1 L-type consumer.

Multiply by 10

Total profit from 10 H-type consumer = 10*6.816 = 68.16

Hence, required overall profit of the seller from 10 consumer of each type will be = 140.92 + 68.16 = 209.08

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