Ans)- Given Profit function-
Π = t – 3q2
Utility function, u = Øq – t
So, u = 8q – t
Since seller has complete information, the utility of consumer will be 0.
So,
u = 8q -t
put u=0
8q – t =0
qL = t/8 --------- (1)
now profit function-
π = t – 3(t/8)2
Differentiate w.r.t. t
dπ/dt = 1 – 6t/64
put dπ/dt=0 [first order condition]
1 = 3t/32
[tL = 10.667] ------------------------------required profit-maximising value of ‘tL hat’.
Put t=10.667 in equation 1
[qL = 10.667/8 = 1.333 ]
So, u = 13q – t
Since seller has complete information, the utility of consumer will be 0.
So,
u = 13q -t
put u=0
13q – t =0
qH = t/13 --------- (2)
now profit function-
π = t – 3(t/13)2
Differentiate w.r.t. t
dπ/dt = 1 – 6t/169
put dπ/dt=0 [first order condition]
1 = 6t/169
[tH = 28.166] ------------------------------required profit-maximising value of ‘tH hat’.
Put t=28.166 in equation 2
[qH = 28.166/13 = 2.166]
Π = t – 3q2
Put t = tH = 28.166
And q =qH =2.166
ΠH = 28.166 – 3(2.166)2
ΠH= 14.092 ----------------------profit from 1 H-type consumer.
Multiply by 10
Total profit from 10 H-type consumer = 10*14.092 = 140.92
Now, Put t = tL = 10.667
And q =qL =1.333
ΠL = 10.667 – 3(1.133)2
ΠL= 6.816 ----------------------profit from 1 L-type consumer.
Multiply by 10
Total profit from 10 H-type consumer = 10*6.816 = 68.16
Hence, required overall profit of the seller from 10 consumer of each type will be = 140.92 + 68.16 = 209.08
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