Question

II. USE THE INFORMATION BELOW TO ANSWER PROBLEMS 6-8 Mark McGwire and Barry Bonds both had record-setting seasons for home runs. The average distance hit for McGwire's homeruns for a 70 game season in 1998 was 418.5 feet with a standard deviation of 45.5 feet. The average distance hit for Bonds' homeruns for a 73 game season in 2001 was 403.7 feet with a standard deviation of 30.6 feet. 6. Choose the best answer below concerning the confidence interval for the difference between the true average distance hit by McGwire and Bonds. a) b) PIZ c) (33–82) -P) 2.4 +84 d) e) 7. None of the above Choose the correct z-value or t-value that would be used in the 95% confidence interval for the difference between the true average distance hit by McGuire and Bonds. a) 11.960 b) 2 1.645 c) t=1656 d) e) 1.977 None of the above 8. If we assign group 1 to be McGwire and group 2 to be Bonds, you may assume the correct 95% confidence interval for the above problem to be (2.0374, 27563). Based on the interval, choose the most appropriate conclusion from the confidence interval from the statements below. We are 95% confident that there is no difference between the true average distance hit by McGwire and Bonds. We are 95% confident that the corresponding true average hit by McGwire is greater a) than that hit by Bonds We are 95% confident that the corresponding true average hit by Bonds is greater than that hit by McGwire. PAGE 1 OF 88 WORDS

Answer 1

Given - n = 70 n = 418,5 , S = 45.5 22 = 73, T = 403.7, S₂ = 30.6 20.05. to = 1.977 confidence interval for difference between true querges is- toica C (x - X 2) + tc S302) ts,? (12-22 1+1 nit ny - 2 correct option is no 1129_o Loic es None of the above son ob apibarri (non 7. correct t-value is wibona d) t 1977 OZEL aniboni n2 The vo 8. given 95%. Ci I is (200374, 27,563) then the conclusion is = ho b) we are 95% confident that the corresponding true average hit by Mc Gwire is greater than that hit by Bonds.

Hit like please.