I know the answer is D, but can someone explain to me how to do this problem? Thanks.
1. Answer: Option D is correct
Explanation:
The probability that II-3 to be heterozygous = 2/3
The probability that II-4 to be heterozygous = 2/3
If both of them are heterozygous,
The probability that their child is unaffected = 2/3 X 2/3 X 1/4 =
1/9
The probability that their child is affected = 1-1/9
= 8/9
I know the answer is D, but can someone explain to me how to do this...
So I know the answer here, but can someone explain to me how to do it and why it's D? Thanks. D Individuals IV-3 and IV-4 got married without knowing that they were related. What is the probability of their first child to have the genetic condition that runs in the family? A. 1/24 B. 1/32 C. 1/48 D. 1/72 E. A different fraction
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