Question

Exit polling is a popular technique used to determine the outcome of an election prior to results being tallied. Suppose a referendum to increase funding for education is on the ballot in a large town​ (voting population over​ 100,000). An exit poll of

300

voters finds that

156

voted for the referendum. How likely are the results of your sample if the population proportion of voters in the town in favor of the referendum is

0.49​?

Based on your​ result, comment on the dangers of using exit polling to call elections.

How likely are the results of your sample if the population proportion of voters in the town in favor of the referendum is

0.49​?

The probability that

more

than

156

people voted for the referendum is

.........??????

​(Round to four decimal places as​ needed.) This is one question that need be awnsered after that awnser last part multiple choice at the bottom

Comment on the dangers of using exit polling to call elections. Choose the correct answer below. This is multiple choice pick the correct answer

A.The result

is

unusual because the probability that

p

is equal to or more extreme than the sample proportion is

greater

than​ 5%. Thus, it

is not

unusual for a wrong call to be made in an election if exit polling alone is considered.

B.The result

is not

unusual because the probability that

p

is equal to or more extreme than the sample proportion is

less

than​ 5%. Thus, it

is

unusual for a wrong call to be made in an election if exit polling alone is considered.

C.The result

is not

unusual because the probability that

p

is equal to or more extreme than the sample proportion is

greater

than​ 5%. Thus, it

is not

unusual for a wrong call to be made in an election if exit polling alone is considered.

D.The result

is

unusual because the probability that

p

is equal to or more extreme than the sample proportion is

less

than​ 5%. Thus, it

is

unusual for a wrong call to be made in an election if exit polling alone is considered

Answer 1

Note: Probability is obtained from Z table

Girn that n = 30 x=156 let 8 = sample proportion= proportion = xn= 156/300 = 0.52 Ginn populata proportich p=0.49 Using Normal approximation (CLT J Pn Normal (up = P, ( Mi= P 5o = P(1-P)/n Required probability is Prob L p> 156/300] = PE p > 0.52 A P Z 0.52-0.49 049805) 300 P [ z 1.0394] Z 104 0.1493 ✓ Answer is