Question

Problem 3: Draw the shear force diagram (SFD) and bending moment diagram (BMD) for the 3-in in diameter shaft and determine the absolute maximum bending stress in the shaft. The shaft is supported by a thrust bearding at A and a journal bearing at B. 3600 lb 1800 lb B 3ft 3ft 3ft

Answer 1

Som- 1800 lb free body daigram- 1-2- 3600 lb A T + 123rt - 4-3ft B 5 T3ft- RA RB leegex - moment Eqn about A (EM)+0 3600X 3 - RBX 6 + 1800X 9 - 6 RB = 4500 lb force emin ५ dish of EFy=0 RA+ RB - 3600+ 1800 * RA goolb 2 2700 lb-ft Section ACCX=0 to 3ft) Sheas force → VX-X= RA - 900 lb VA=Vc Bending moment & Mx-x: goox MA=0 Me=goox 3 Section CB(x: 3ft to 6ft) Shear force =D Yxxa 900-3600 =- 2700 1b = Ye: VG B.M > Mxx - 9007 - 3600(2-3) ► Mc-2700 lb-ft MB - 540016 Section Bo (2= 6 to 9 ft) -ft 1800lb - VB Vo ? Mxx= - 1800 (9-x) My=0, MB = - 5400 lb-ft Ver

Shear force doigram- 1800 lb 900 lb А B 느 • 2700 lb Bending - moment daigram 2700 lb-ft А с B 5400 lb-ft # Maxe" absolute Bending stress Mann absolute Bending moment: M. 5400 lb-ft M-5400X12 64800 lb-in M max Z M 7/3243 32M ñ a3 more 32864800 XX (3) maxi • 24446.1992 psi Omane 24. 446 Ksi
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