Question

For the beam shown below, find the maximum bending stress and maximum transverse shear stress. That is, carry out load and stress analyses in the following order. Load Analysis Draw the load diagram or free body diagram (FBD) and determine the support reactions. Show your calculations. • Draw the shear force diagram (SFD). Show your calculations. Draw the bending moment diagram (BMD). Show your calculations. Stress Analysis Identify the critical section(s) and determine the maximum normal (bending) stress at the section(s). Identify the critical section(s) and determine the shear (transverse) stress at the section(s). 15 KN 5 kN A. Load Analysis A 1.FBD 18 mm 0 25 mm 375 mm BA25 mm 50 mm 15/kN 5 kN TA B С A2 SFD 25 mm 375 mat RA RE V (NA A.MD (mm) M N.mm Page 1 of 5 260 words

Answer 1

Given that 5 kn 15 KN А RA= 14.667 kn RB-5.33 kn K 25 mm k 375mm Sk 25 mm 5KN 5KA С o F033 IN 033 KN B С - 125 Nom from the eavilibrium Conditions EMAD (RB) (375) = (5)(335+25) RB=5.33 KN Efy = 0 -> RATRB= 20 kN a RA 14.667 KN

SFB= 5-5.33 = -0.33 KN Shear force - SFc = Bending moment 5 KN Mo=0 MB=(-5)(0.025) SFA-5-5.33 = -0.33 KD =-0.125 KN.M 125 Nm - The manimum sheas fora is at MA= (5) Co.u) + (5.333) (0.375) Point B- ISPman SF g = 55 kn MA = OKNim. - maximum Bending moment is at point B. mo taman = -125 Nim 18 mm marimom Bending stress Cat Point B) 50 ) (66) man 6m bd2 (6) (125) (103) (18) (50) 06) man = 16.67 MPa - tens' ~ at Point B 8 - moment m= -125 Nm is hogging moment Compree manimom transvease shear storess : Cat Point B) of Eman ENIA a) (zowy eman = (3/2) Sfman) () D 5000 (50x18 ) Eman = Poin = 8.33 MPa - at Point B at Neutral an