Question

520/take Question 1 50 pts The Young double-slits with 51.8 um separation between the slits is illuminated with 513.4 nm. If a viewing screen is located 2.4 m from the slits, find the distance (in meters) from the first dark fringe on one side of the central maximum to the second bright fringe on the other side (please read the problem carefully). Question 2 50 pts The spacing of ruled lines on a diffraction grating is 1,517 nm. The grating is illuminated at normal incidence with a parallel beam of white light in the 395.2 nm to 700 nm wavelength band. The angular width of the gap between the first order spectrum and the second order spectrum is closest to (in degree);

Answer 1

Answers U Given, d = 51.8 um 51.88106m 2 0 2 513,40m 2 51314x 10 9 m D z 2, um on upper side first dark koin ge (1-22 1 / 2 (2D) y, Second dark fóinge on other side. AD Y = -2ZD d. 2D distance 4y - Y - Y₂ (-20) 220 2D + 2d 52D 20 2 5x 5 13 14x10 9 x 2,4 2x 51, 8x106 laya 0.059467 m 259 467mm

Answeo 8 a 1517x10m - 1519 nm 2, R = 700 mm = 100x109 m 2X2 2 395.2. nm 395.2 x 10 9 m order Spectrum 0 15178 109 sino, 21 - 9 1578 109x sino = 700x15 700x109 0 = sin ond sind, 2 15178159 700X169 1517815 227,4790 ovdor Spectoum 15178 10 9 x sinO2= 2x22 2X 395.2 x 159 15174109 Sin (2x395.21 02 2 1517 31. you Angular width = 10 = 31.401 - 27.479) 10 = 31922°