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Question 6 1 pts A light bulb with a resistance of 2982 draws 56 milliamps of current when attached to a 20 volt battery (i.e

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internal resistance of battery Lets consider the > so, v=P(R+r) i 20 56610-3 = 357.14 R+8=Ť = r = 357.14- 298 -59.1482 (Aus)

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