Question

A 3.00 pF capacitor is connected in series with a 2.00 pF capacitor and a 630 V potential difference is applied across the pair. (a) What is the charge on each capacitor (in nC)? 3.00 pF capacitor 1.42 2.00 pF capacitor 1.08 xnc xnc (b) What is the voltage across each capacitor (in V)? 3.00 pF capacitor 2.00 pF capacitor V V

Answer 1

Solh a) Capaciton 3.00PF in Series So their equivalent and 2.00PF are conneched Ceq = 3x2 3+2 Ceq = 1.2 PF Change on each capaciton , &=&=82 8 = Ceau 1.2x10-1 X 630 = 7.56 x 10-10 c 0.756 nc 0.756 ne 3.00 PF capacitor 2.00 pF capacitor D. 756 nc b) voltage ορ ΠρRS 3.00pF Capaciton 0.756x10-9 V= 3x10-12 V = 252 V Voltage across 2.00PF capacitor 0.1756 x 109 2 x1072 D V2 = cz V2 = 378 v v 3.00 PE 252 capacitor capacitor 2.00 P 378