Homework Answers
By convention, pH is equal to pKa at half equivalence point. So, the pKa of acid is 3.42.
Ka = 10-pKa = 10-3.42
= 3.80189 × 10-4
= 3.80 × 10-4
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Not sure if I did number 4 correct.
The
half way point was 7.89mL with a...
The half‑equivalence point of a titration occurs half way to the equivalence point, where half of...
The half‑equivalence point of a titration occurs half way to the
equivalence point, where half of the analyze has reacted to form
its conjugate, and the other half still remains unreacted.
If 0.4400.440 moles of a monoprotic weak acid
(?a=7.2×10−5)(Ka=7.2×10−5) is titrated with NaOH,NaOH, what is the
pH of the solution at the half‑equivalence point?
pH=pH=
2)
A volume of 500.0 mL500.0 mL of 0.120 M0.120 M NaOHNaOH is added
to 565 mL565 mL of 0.250 M0.250 M weak acid...
Not sure about my answers. So I would like to see Half equivilance point, pKa, Ka...
Not sure about my answers. So I would like to see Half
equivilance point, pKa, Ka and molarity of acid values worked out
from these graphs. Impotant data: titration of 25.00 +/- 0.01 mL of
unknown acid by 0.1069 M NaOh. Two runs were done, but data
calculations for ony one is needed now (they sets are nearly
identical)..
12 10 pH Titration Curves (pH vs. mL NaoH) eequiv. Rint 25 NaOH (mL) inch 9 inch Trial 1 CT.) e...
It's a weak acid strong base titration Experiment 4: Identification of an unknown acid by titration...
It's a weak acid strong base titration
Experiment 4: Identification of an unknown acid by titration Page 2 of 15 Background In this experiment, you will use both qualitative and quantitative properties to determine an unknown acid's identity and concentration. To do this analysis, you will perform a titration of your unknown acid sample-specifically a potentiometric titration where you use a pH meter and record pH values during the titration, combined with a visual titration using a color indi- cator...
The half‑equivalence point of a titration occurs half way to the
equivalence point, where half of the analyze has reacted to form
its conjugate, and the other half still remains unreacted.
If 0.4400.440 moles of a monoprotic weak acid
(?a=7.2×10−5)(Ka=7.2×10−5) is titrated with NaOH,NaOH, what is the
pH of the solution at the half‑equivalence point?
pH=pH=
2)
A volume of 500.0 mL500.0 mL of 0.120 M0.120 M NaOHNaOH is added
to 565 mL565 mL of 0.250 M0.250 M weak acid...
Not sure about my answers. So I would like to see Half
equivilance point, pKa, Ka and molarity of acid values worked out
from these graphs. Impotant data: titration of 25.00 +/- 0.01 mL of
unknown acid by 0.1069 M NaOh. Two runs were done, but data
calculations for ony one is needed now (they sets are nearly
identical)..
12 10 pH Titration Curves (pH vs. mL NaoH) eequiv. Rint 25 NaOH (mL) inch 9 inch Trial 1 CT.) e...
It's a weak acid strong base titration
Experiment 4: Identification of an unknown acid by titration Page 2 of 15 Background In this experiment, you will use both qualitative and quantitative properties to determine an unknown acid's identity and concentration. To do this analysis, you will perform a titration of your unknown acid sample-specifically a potentiometric titration where you use a pH meter and record pH values during the titration, combined with a visual titration using a color indi- cator...
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