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Not sure about my answers. So I would like to see Half equivilance point, pKa, Ka and molarity of acid values worked out from these graphs. Impotant data: titration of 25.00 +/- 0.01 mL of unknown acid by 0.1069 M NaOh. Two runs were done, but data calculations for ony one is needed now (they sets are nearly identical).12 10 pH Titration Curves (pH vs. mL NaoH) eequiv. Rint 25 NaOH (mL) inch 9 inch Trial 1 CT.) e Trial 2 2 per. Mov. Avg. (Trial 2 45.

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Page No, Date Volume of acid2m velume of NaotR 8m at ivalence ーMokeme -4.18 Ntote 9.43732 e

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