Question
there is a current of .25 A in the circuit shown.
what is the direction of the current?
what is the value of the resistor R?
what is the power dissipated by R?

6.0 0. 120 w 6.0 v 12 V R www
0 0
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Answer #1

boninen gi 12V R I n Tor Here, both batteries are try to flow corrent in opposite direction. so net emf. 12- 6 = 6 VoHS. so dPower dissipated by R. RR = (²) 2 x 6 PR = Ix83 il 168 Pe = 0.375 W

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